2005. Subtree Removal Game with Fibonacci Tree
Problem Description
In this problem, Alice and Bob are playing a game with a Fibonacci tree. A Fibonacci tree is a binary tree created using the order function order(n)
. The game proceeds as follows:
- Alice starts first.
- On each turn, a player selects a node from the tree and removes that node along with its subtree.
- The player is forced to delete the root node and loses the game.
Our task is to return true
if Alice wins the game or false
if Bob wins, assuming both players play optimally. A subtree of a binary tree consists of a node in the tree and all of this node's descendants. The tree itself could also be considered as a subtree of itself.
Example
Let's take n = 7
.
According to the solution, when Alice starts first and plays optimally, the function findGameWinner(7)
should return true
, meaning Alice will win the game. The remainder of 7 % 6 is not 1, so the solution returns true for Alice's winning.
Solution Approach
The pattern in this problem is that if the number n
is such that n % 6 != 1
, then Alice will win. Otherwise, Bob wins. This pattern uses simple modulo arithmetic.
The solution to this problem is provided as follows using a simple Boolean function in a class called Solution
.
Python Solution
1 2python 3class Solution: 4 def findGameWinner(self, n: int) -> bool: 5 return n % 6 != 1
Java Solution
1
2java
3public class Solution {
4 public boolean findGameWinner(int n) {
5 return n % 6 != 1;
6 }
7}
JavaScript Solution
1 2javascript 3class Solution { 4 findGameWinner(n) { 5 return n % 6 !== 1; 6 } 7}
C++ Solution
1
2cpp
3class Solution {
4public:
5 bool findGameWinner(int n) {
6 return n % 6 != 1;
7 }
8};
C# Solution
1
2csharp
3public class Solution {
4 public bool FindGameWinner(int n) {
5 return n % 6 != 1;
6 }
7}
Conclusion
This problem is based on a simple pattern using modulo arithmetic. By following the provided solution approach and using a simple Boolean function, we can easily find out if Alice will win the game or not when she plays optimally. The solutions are provided in Python, Java, JavaScript, C++, and C# languages.Overall, understanding the pattern in the Fibonacci tree game problem is crucial to providing an optimal solution. By recognizing that if the number n
is such that n % 6 != 1
, Alice wins, we can quickly determine the game's outcome with minimal code and computation. This approach results in efficient solutions provided in various programming languages, including Python, Java, JavaScript, C++, and C#.
What's the output of running the following function using input 56
?
1KEYBOARD = {
2 '2': 'abc',
3 '3': 'def',
4 '4': 'ghi',
5 '5': 'jkl',
6 '6': 'mno',
7 '7': 'pqrs',
8 '8': 'tuv',
9 '9': 'wxyz',
10}
11
12def letter_combinations_of_phone_number(digits):
13 def dfs(path, res):
14 if len(path) == len(digits):
15 res.append(''.join(path))
16 return
17
18 next_number = digits[len(path)]
19 for letter in KEYBOARD[next_number]:
20 path.append(letter)
21 dfs(path, res)
22 path.pop()
23
24 res = []
25 dfs([], res)
26 return res
27
1private static final Map<Character, char[]> KEYBOARD = Map.of(
2 '2', "abc".toCharArray(),
3 '3', "def".toCharArray(),
4 '4', "ghi".toCharArray(),
5 '5', "jkl".toCharArray(),
6 '6', "mno".toCharArray(),
7 '7', "pqrs".toCharArray(),
8 '8', "tuv".toCharArray(),
9 '9', "wxyz".toCharArray()
10);
11
12public static List<String> letterCombinationsOfPhoneNumber(String digits) {
13 List<String> res = new ArrayList<>();
14 dfs(new StringBuilder(), res, digits.toCharArray());
15 return res;
16}
17
18private static void dfs(StringBuilder path, List<String> res, char[] digits) {
19 if (path.length() == digits.length) {
20 res.add(path.toString());
21 return;
22 }
23 char next_digit = digits[path.length()];
24 for (char letter : KEYBOARD.get(next_digit)) {
25 path.append(letter);
26 dfs(path, res, digits);
27 path.deleteCharAt(path.length() - 1);
28 }
29}
30
1const KEYBOARD = {
2 '2': 'abc',
3 '3': 'def',
4 '4': 'ghi',
5 '5': 'jkl',
6 '6': 'mno',
7 '7': 'pqrs',
8 '8': 'tuv',
9 '9': 'wxyz',
10}
11
12function letter_combinations_of_phone_number(digits) {
13 let res = [];
14 dfs(digits, [], res);
15 return res;
16}
17
18function dfs(digits, path, res) {
19 if (path.length === digits.length) {
20 res.push(path.join(''));
21 return;
22 }
23 let next_number = digits.charAt(path.length);
24 for (let letter of KEYBOARD[next_number]) {
25 path.push(letter);
26 dfs(digits, path, res);
27 path.pop();
28 }
29}
30
Solution Implementation
Which algorithm should you use to find a node that is close to the root of the tree?
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