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2703. Return Length of Arguments Passed

Problem Description

The problem asks you to write a function called argumentsLength that counts and returns the number of arguments passed to it.

The function should accept any number of arguments (of any type) and simply return how many arguments were provided when the function was called.

For example:

  • If you call argumentsLength(1, 2, 3), it should return 3 because three arguments were passed
  • If you call argumentsLength("hello", true, 42, [1, 2]), it should return 4 because four arguments were passed
  • If you call argumentsLength() with no arguments, it should return 0

The solution uses the rest parameter syntax ...args to collect all arguments into an array, then returns the length of that array using args.length. This approach works regardless of the number or types of arguments passed to the function.

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Intuition

When we need to count the number of arguments passed to a function, we face a challenge: we don't know in advance how many arguments will be provided. The function could be called with zero arguments, three arguments, or even a hundred arguments.

JavaScript (and TypeScript) provides a perfect tool for this scenario: the rest parameter syntax (...). This syntax allows us to capture all arguments passed to a function, regardless of their quantity, and bundle them into an array.

Once we have all the arguments collected in an array, counting them becomes trivial - we just need to check the array's length property. The ...args syntax essentially transforms the problem from "count an unknown number of separate arguments" to "find the length of an array", which is a simple operation.

This approach is elegant because:

  1. It handles any number of arguments automatically
  2. It doesn't require us to specify individual parameters
  3. The solution is just one line of code: return args.length

The rest parameter ...args: any[] acts like a collector that gathers all arguments into a single array structure, making the counting operation straightforward.

Solution Approach

The implementation uses JavaScript/TypeScript's rest parameter feature to solve this problem elegantly.

Implementation Details:

  1. Function Declaration with Rest Parameters:

    function argumentsLength(...args: any[]): number
    • The ...args syntax is the rest parameter that collects all arguments
    • any[] indicates that args is an array that can contain elements of any type
    • The function returns a number (the count of arguments)
  2. Counting the Arguments:

    return args.length;
    • Since all arguments are collected into the args array, we simply return its length property
    • This automatically gives us the count of arguments passed

How It Works:

When the function is called with any number of arguments, the rest parameter ...args performs the following:

  • Collects all individual arguments into a single array
  • For example, calling argumentsLength(1, 2, 3) transforms the three separate arguments into args = [1, 2, 3]
  • The length property of this array gives us 3

Key Pattern Used:

This solution leverages the variadic function pattern through rest parameters, which is a common pattern for handling functions with a variable number of arguments. The pattern converts the problem of counting separate parameters into a simple array length operation.

The beauty of this approach is its simplicity and universality - it works with any number of arguments (including zero) and any types of arguments without modification.

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Example Walkthrough

Let's walk through how the solution works with a concrete example:

Example Call: argumentsLength(5, "hello", true)

Step-by-step execution:

  1. Function is called with three arguments:

    • First argument: 5 (number)
    • Second argument: "hello" (string)
    • Third argument: true (boolean)
  2. Rest parameter collects arguments:

    • The ...args syntax captures all three arguments
    • These arguments are placed into an array: args = [5, "hello", true]
    • This happens automatically when the function is invoked
  3. Array length is calculated:

    • The function executes return args.length
    • Since args contains three elements, args.length equals 3
  4. Result returned:

    • The function returns 3

Visual representation of the transformation:

argumentsLength(5, "hello", true)
         ...args captures all
    args = [5, "hello", true]
        args.length = 3
           returns 3

Another example with no arguments:

  • Call: argumentsLength()
  • Rest parameter creates: args = [] (empty array)
  • Returns: args.length = 0

This demonstrates how the rest parameter syntax elegantly converts the problem of counting individual arguments into simply checking an array's length, handling any number of arguments seamlessly.

Solution Implementation

1def argumentsLength(*args):
2    """
3    Calculates the number of arguments passed to the function
4  
5    Args:
6        *args: Variable number of arguments of any type
7  
8    Returns:
9        int: The count of arguments passed
10    """
11    # Return the length of the arguments tuple
12    return len(args)
13
14
15# Example usage:
16# argumentsLength(1, 2, 3)  # Returns: 3
17# argumentsLength("a", "b")  # Returns: 2
18# argumentsLength()         # Returns: 0
19
1/**
2 * Calculates the number of arguments passed to the function
3 * @param args - Variable number of arguments of any type
4 * @return The count of arguments passed
5 */
6public class ArgumentCounter {
7  
8    /**
9     * Method to count the number of arguments passed
10     * @param args - Variable number of arguments of type Object to accept any type
11     * @return The count of arguments passed
12     */
13    public static int argumentsLength(Object... args) {
14        // Return the length of the arguments array
15        return args.length;
16    }
17  
18    /**
19     * Example usage demonstration
20     */
21    public static void main(String[] args) {
22        // Example 1: Passing three integer arguments
23        System.out.println(argumentsLength(1, 2, 3)); // Returns: 3
24      
25        // Example 2: Passing two string arguments
26        System.out.println(argumentsLength("a", "b")); // Returns: 2
27      
28        // Example 3: Passing no arguments
29        System.out.println(argumentsLength()); // Returns: 0
30      
31        // Example 4: Passing mixed type arguments
32        System.out.println(argumentsLength(1, "hello", 3.14, true)); // Returns: 4
33    }
34}
35
1#include <iostream>
2#include <cstdarg>
3
4/**
5 * Calculates the number of arguments passed to the function
6 * Note: In C++, we need to use template variadic functions or 
7 * provide a way to determine the number of arguments
8 */
9
10// Solution 1: Using variadic templates (C++11 and later)
11template<typename... Args>
12int argumentsLength(Args... args) {
13    // Return the number of arguments using sizeof...
14    return sizeof...(args);
15}
16
17// Alternative Solution 2: Using recursive template approach
18/*
19template<typename First, typename... Rest>
20int argumentsLength(First first, Rest... rest) {
21    // Recursively count arguments
22    return 1 + argumentsLength(rest...);
23}
24
25// Base case for recursion
26int argumentsLength() {
27    return 0;
28}
29*/
30
31/**
32 * Example usage:
33 * argumentsLength(1, 2, 3); // Returns: 3
34 * argumentsLength("a", "b"); // Returns: 2
35 * argumentsLength(); // Returns: 0
36 */
37
38// Example main function to demonstrate usage
39int main() {
40    std::cout << argumentsLength(1, 2, 3) << std::endl;  // Output: 3
41    std::cout << argumentsLength("a", "b") << std::endl; // Output: 2
42    std::cout << argumentsLength() << std::endl;         // Output: 0
43  
44    return 0;
45}
46
1/**
2 * Calculates the number of arguments passed to the function
3 * @param args - Variable number of arguments of any type
4 * @returns The count of arguments passed
5 */
6function argumentsLength(...args: any[]): number {
7    // Return the length of the arguments array
8    return args.length;
9}
10
11/**
12 * Example usage:
13 * argumentsLength(1, 2, 3); // Returns: 3
14 * argumentsLength("a", "b"); // Returns: 2
15 * argumentsLength(); // Returns: 0
16 */
17

Time and Space Complexity

Time Complexity: O(1)

The function argumentsLength performs a single operation - accessing the length property of the args array. In JavaScript/TypeScript, the length property of an array is maintained as a metadata field and accessing it is a constant-time operation. The rest parameter ...args collects all arguments into an array during the function call, which happens in O(n) time where n is the number of arguments. However, since this collection happens as part of the function invocation mechanism before the function body executes, and the function body itself only accesses the length property, the time complexity of the function's execution is O(1).

Space Complexity: O(n)

The rest parameter ...args creates a new array that contains all the arguments passed to the function. This array requires O(n) space where n is the number of arguments passed. Even though we only access the length property and don't perform any operations on the array elements, the array itself is still created in memory to hold all the arguments.

Common Pitfalls

1. Confusing Rest Parameters with the arguments Object

A common mistake is trying to use the deprecated arguments object instead of rest parameters, especially when working with older JavaScript code or when transitioning from older patterns.

Incorrect approach:

function argumentsLength() {
    return arguments.length;  // Works in regular functions but not in arrow functions
}

Problems with this approach:

  • The arguments object is not available in arrow functions
  • It's not a real array, so array methods don't work directly on it
  • It's considered legacy and less performant than rest parameters

Correct solution:

// Use rest parameters instead
function argumentsLength(...args) {
    return args.length;
}

2. Attempting to Pass an Array Directly

Another pitfall occurs when trying to pass an existing array to count its elements, expecting the function to count the array's contents rather than treating the array as a single argument.

Misunderstanding:

const myArray = [1, 2, 3, 4, 5];
argumentsLength(myArray);  // Returns 1, not 5!

The function counts the array as ONE argument, not its individual elements.

Solution if you need to count array elements:

// Use the spread operator to expand the array
argumentsLength(...myArray);  // Returns 5

// Or modify the function to handle both cases
function flexibleArgumentsLength(...args) {
    // Check if single array argument
    if (args.length === 1 && Array.isArray(args[0])) {
        return args[0].length;  // Return array's length
    }
    return args.length;  // Return number of arguments
}

3. Type Confusion in TypeScript

When using TypeScript, developers might incorrectly type the rest parameter, limiting its flexibility.

Incorrect typing:

function argumentsLength(...args: number[]): number {
    return args.length;  // Only accepts numbers!
}

Correct typing for maximum flexibility:

function argumentsLength(...args: any[]): number {
    return args.length;  // Accepts any types
}

// Or use unknown[] for better type safety
function argumentsLength(...args: unknown[]): number {
    return args.length;
}

4. Forgetting That Rest Parameters Create a New Array

Each function call creates a new array for the rest parameters, which could have performance implications in performance-critical scenarios with frequent calls.

Potential issue in loops:

// This creates many temporary arrays
for (let i = 0; i < 1000000; i++) {
    argumentsLength(1, 2, 3, 4, 5);  // New array created each time
}

Solution for performance-critical code: If counting arguments in a tight loop, consider alternative approaches or caching results when the argument pattern is predictable.

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You are given an array of intervals where intervals[i] = [start_i, end_i] represent the start and end of the ith interval. You need to merge all overlapping intervals and return an array of the non-overlapping intervals that cover all the intervals in the input.


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