2890. Reshape Data Melt
Problem Description
The given LeetCode problem presents a DataFrame
named report
which contains sales data for different products across four quarters (quarter_1, quarter_2, quarter_3, quarter_4). Each row of this DataFrame
represents a product and the sales figures for each of the four quarters are in separate columns. The task is to reshape this data such that the resulting DataFrame
has a row for each product and quarter combination. Essentially, it involves converting the wide format of the DataFrame
(where quarters are spread across columns) into a long format (where quarter data is stacked into single column with corresponding sales figures).
The expected output is a DataFrame
with three columns: 'product', 'quarter', and 'sales'. Each row should contain a product name, a specific quarter, and the sales for that product in that quarter.
Intuition
The intuition behind the solution is that we want to "melt" the wide DataFrame
into a long DataFrame
. In pandas, the melt
function is used for just such a transformation. It takes the following parameters:
id_vars
: The column(s) of the oldDataFrame
to preserve as identifier variables. In this case, it's the 'product' column, as we want to keep that fixed for each entry.var_name
: The name to give the variable column that will hold the names of the former columns. We will name it 'quarter' since it will contain the names of the quarter columns.value_name
: The name to give the value column that will contain the values from the former quarter columns. We'll call this 'sales' to indicate that these values represent the sales amounts.
By applying the melt
method to the report
dataframe, it will take each entry from the quarter-specific columns and place it into its own row, associated with the appropriate product and tagged with the corresponding quarter, achieving the desired reshaping of the data.
Solution Approach
The solution makes use of the melt
function from the pandas library. This function is designed to transform a DataFrame from a wide format to a long format, which is exactly what is required in the problem. The melt
function can be seen as a way to 'unpivot' or 'reshape' the data.
Here's a step-by-step walkthrough of the meltTable
function shown in the reference solution:
- We start by passing the
report
DataFrame to themeltTable
function. - Within the function, we call
pd.melt
on thereport
DataFrame.
The pd.melt
function is called with the following arguments:
id_vars=['product']
: This specifies that the 'product' column should stay as is and not be unpivoted. This column is used as the identifier variable.var_name='quarter'
: This argument tells pandas to name the new column that holds the 'variables', which were originally the column names (quarter_1, quarter_2, quarter_3, quarter_4), as 'quarter'.value_name='sales'
: This specifies that the new column that holds the values from the variable columns should be named 'sales'.
The melt
function processes the DataFrame report
by keeping the 'product' column fixed and ‘melting’ the quarter columns. For each product, it creates a new row for each quarter column, filling in the 'quarter' column with the quarter column name (e.g., 'quarter_1') and the 'sales' column with the corresponding sales value.
As a result, what was previously structured as one row per product with multiple columns for each quarter becomes multiple rows for each product, with each row representing a different quarter.
By using pandas and its melt
function, the solution effectively harnesses the power of an established data manipulation tool to accomplish the task in a concise and efficient manner without the need for writing complex data reshaping code from scratch.
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Start EvaluatorExample Walkthrough
Let's say we have the following small 'report' DataFrame as an example:
product | quarter_1 | quarter_2 | quarter_3 | quarter_4 |
---|---|---|---|---|
ProductA | 150 | 200 | 250 | 300 |
ProductB | 100 | 150 | 200 | 250 |
We want to reshape this data to create a 'long' format DataFrame, where each product and quarter combination gets its own row. Here's how we apply the solution approach:
- We pass this 'report' DataFrame to our
meltTable
function. - Inside
meltTable
, we usepd.melt
and specify three key parameters:id_vars=['product']
ensures that the 'product' column is preserved in the transformation.var_name='quarter'
creates a new column named 'quarter', which will contain the names of the original columns that represented each quarter.value_name='sales'
specifies that the values from those quarter columns should be placed in a new column called 'sales'.
After calling pd.melt
with these parameters, we get the following DataFrame:
product | quarter | sales |
---|---|---|
ProductA | quarter_1 | 150 |
ProductA | quarter_2 | 200 |
ProductA | quarter_3 | 250 |
ProductA | quarter_4 | 300 |
ProductB | quarter_1 | 100 |
ProductB | quarter_2 | 150 |
ProductB | quarter_3 | 200 |
ProductB | quarter_4 | 250 |
The resulting DataFrame has the three columns: 'product', 'quarter', and 'sales', with each row containing a specific combination of product and quarter with the corresponding sales figure. This transformation enables a more detailed analysis of sales data by quarter for each product.
Solution Implementation
1import pandas as pd # Import the pandas library with alias 'pd'
2
3def melt_table(report: pd.DataFrame) -> pd.DataFrame:
4 # Function to transform the input DataFrame into a format where each row
5 # represents a single observation for a specific quarter and product.
6
7 # 'pd.melt': Convert the given DataFrame from wide format to long format.
8 # 'id_vars': Column(s) to use as identifier variables.
9 # 'var_name': Name of the new column created after melting that will hold the variable names.
10 # 'value_name': Name of the new column created that will contain the values.
11 melted_report = pd.melt(report, id_vars=['product'], var_name='quarter', value_name='sales')
12 return melted_report # Return the melted DataFrame
13
14# Usage example (not part of the required code rewrite, for illustration purposes):
15# Assuming 'report' is a DataFrame structured with 'product' as one of the columns
16# and other columns represent sales data for each quarter.
17# Example structure of 'report' before melting:
18# product Q1 Q2 Q3 Q4
19# A 10 15 20 25
20# B 5 10 15 20
21# After calling melt_table(report), the result will be:
22# product quarter sales
23# A Q1 10
24# B Q1 5
25# A Q2 15
26# B Q2 10
27# ...and so on for each product and quarter.
28
1import java.util.ArrayList;
2import java.util.HashMap;
3import java.util.List;
4import java.util.Map;
5
6class SalesReport {
7
8 // A method to transform a report into a melted format where each row represents a single observation
9 public static List<Map<String, String>> meltTable(List<Map<String, String>> report) {
10 List<Map<String, String>> meltedReport = new ArrayList<>();
11
12 // Loop over each row (each map is a row with the product and sales data)
13 for (Map<String, String> row : report) {
14 String product = row.get("product");
15 // Loop over each entry in the map, which represents the columns in the original table
16 for (Map.Entry<String, String> entry : row.entrySet()) {
17 if (!entry.getKey().equals("product")) { // Ignore the product column for melting
18 // Create a new map for the melted row
19 Map<String, String> meltedRow = new HashMap<>();
20 meltedRow.put("product", product);
21 meltedRow.put("quarter", entry.getKey()); // The column name becomes the quarter
22 meltedRow.put("sales", entry.getValue()); // The value remains the sale amount
23 meltedReport.add(meltedRow);
24 }
25 }
26 }
27 return meltedReport; // Return the melted table
28 }
29
30 // Example usage
31 public static void main(String[] args) {
32 List<Map<String, String>> report = new ArrayList<>();
33 Map<String, String> row1 = new HashMap<>();
34 row1.put("product", "A");
35 row1.put("Q1", "10");
36 row1.put("Q2", "15");
37 row1.put("Q3", "20");
38 row1.put("Q4", "25");
39 report.add(row1);
40
41 Map<String, String> row2 = new HashMap<>();
42 row2.put("product", "B");
43 row2.put("Q1", "5");
44 row2.put("Q2", "10");
45 row2.put("Q3", "15");
46 row2.put("Q4", "20");
47 report.add(row2);
48
49 List<Map<String, String>> meltedReport = meltTable(report);
50
51 // Print melted report
52 for (Map<String, String> meltedRow : meltedReport) {
53 System.out.println(meltedRow);
54 }
55 }
56}
57
1#include <pandas/pandas.h> // Include the pandas C++ library (note: a C++ pandas-like library doesn't exist, but assuming it for the purpose of the exercise.)
2
3class ReportTransformer {
4public:
5 // Transforms the input DataFrame into a format where each row represents a single observation for a specific quarter and product.
6 pandas::DataFrame meltTable(const pandas::DataFrame& report) const {
7 // 'melt': Convert the given DataFrame from wide format to long format.
8 // 'idVars': Vector of column names to use as identifier variables.
9 // 'varName': Name of the new column created after melting that will hold the variable names.
10 // 'valueName': Name of the new column created that will contain the values.
11 pandas::DataFrame meltedReport = report.melt(
12 {"product"}, // idVars
13 "quarter", // varName
14 "sales" // valueName
15 );
16
17 return meltedReport; // Return the melted DataFrame
18 }
19};
20
21// Usage example:
22// Assuming 'report' is a pandas::DataFrame structured with 'product' as one of the columns
23// and other columns represent sales data for each quarter like Q1, Q2, Q3, Q4.
24// Example structure of 'report' before melting:
25// product Q1 Q2 Q3 Q4
26// A 10 15 20 25
27// B 5 10 15 20
28// After calling meltTable(report), the result will be:
29// product quarter sales
30// A Q1 10
31// B Q1 5
32// A Q2 15
33// B Q2 10
34// ...and so on for each product and quarter.
35
1interface ProductReport {
2 product: string;
3 [key: string]: string | number; // Represents sales data for each quarter with dynamic keys
4}
5
6interface MeltedReport {
7 product: string;
8 quarter: string;
9 sales: number;
10}
11
12function meltTable(report: ProductReport[]): MeltedReport[] {
13 // Function to transform the input array of objects into a format
14 // where each entry represents a single observation for a specific quarter and product.
15
16 let meltedReport: MeltedReport[] = [];
17
18 // Loop over each product report
19 report.forEach((productReport) => {
20 // Loop over each property in the product report object
21 for (const [key, value] of Object.entries(productReport)) {
22 // Skip the 'product' key as it's the identifier
23 if (key !== 'product') {
24 // Create an object for each quarter with sales data and push it into the meltedReport array
25 meltedReport.push({
26 product: productReport.product,
27 quarter: key,
28 sales: value as number // Assuming the value is always a number for sales data
29 });
30 }
31 }
32 });
33
34 return meltedReport; // Return the transformed data
35}
36
37// Usage example:
38// Assuming 'report' is an array of objects structured with 'product' as one of the properties
39// and other properties represent sales data for each quarter.
40// Example structure of 'report' before melting:
41// [
42// { product: 'A', Q1: 10, Q2: 15, Q3: 20, Q4: 25 },
43// { product: 'B', Q1: 5, Q2: 10, Q3: 15, Q4: 20 }
44// ]
45// After calling meltTable(report), the result will be:
46// [
47// { product: 'A', quarter: 'Q1', sales: 10 },
48// { product: 'A', quarter: 'Q2', sales: 15 },
49// ...
50// { product: 'B', quarter: 'Q1', sales: 5 },
51// { product: 'B', quarter: 'Q2', sales: 10 },
52// ...
53// ]
54
Time and Space Complexity
Time Complexity
The meltTable
function involves the pd.melt
operation from pandas. The time complexity of this operation depends on the size of the input DataFrame. If we assume the input DataFrame has m
rows (excluding the header) and n
columns (including the 'product' column), then the pd.melt
function would iterate through all (m * (n - 1))
elements once, converting them into (m * (n - 1))
rows of the melted DataFrame. Thus, the time complexity is O(m * (n - 1))
, which simplifies to O(m * n)
.
Space Complexity
Regarding the space complexity, pd.melt
generates a new DataFrame that has (m * (n - 1))
rows and 3 columns (['product', 'quarter', 'sales']
). Hence, the space required for the new DataFrame is proportional to the number of elements in this new structure, which gives us the space complexity of O(m * (n - 1) * 3)
. Since we tend to ignore constant factors in Big O notation, this simplifies to O(m * n)
.
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