1853. Convert Date Format

Problem

Given a table Days with a day column of date type, the goal is to write an SQL query that will convert each date in the table into a string formatted as "day_name, month_name day, year". The result table should be returned in any order, and the output must be case-sensitive.

Example

Consider the following Days table:

+------------+
| day        |
+------------+
| 2022-04-12 |
| 2021-08-09 |
| 2020-06-26 |
+------------+

The expected query result would be:

+-------------------------+
| day                     |
+-------------------------+
| Tuesday, April 12, 2022 |
| Monday, August 9, 2021  |
| Friday, June 26, 2020   |
+-------------------------+

Approach

To solve this problem, MySQL's DATE_FORMAT function can be used. This function allows you to format a date value based on a given format pattern. The following format pattern can be used to achieve the required output:

%W, %M %e, %Y

This pattern will replace %W with the day name, %M with the month name, %e for the day number without leading zeros, and %Y for the year.

Example

Let's walk through the problem example using this approach:

2022-04-12 -> DATE_FORMAT('2022-04-12', '%W, %M %e, %Y') -> Tuesday, April 12, 2022
2021-08-09 -> DATE_FORMAT('2021-08-09', '%W, %M %e, %Y') -> Monday, August 9, 2021
2020-06-26 -> DATE_FORMAT('2020-06-26', '%W, %M %e, %Y') -> Friday, June 26, 2020

Solution

SQL

To achieve the required result, we can write an SQL query as follows:

SELECT DATE_FORMAT(day, '%W, %M %e, %Y') AS day
FROM Days;

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Question 1 out of 10

Given a sorted array of integers and an integer called target, find the element that equals to the target and return its index. Select the correct code that fills the ___ in the given code snippet.

1def binary_search(arr, target):
2    left, right = 0, len(arr) - 1
3    while left ___ right:
4        mid = (left + right) // 2
5        if arr[mid] == target:
6            return mid
7        if arr[mid] < target:
8            ___ = mid + 1
9        else:
10            ___ = mid - 1
11    return -1
12

1public static int binarySearch(int[] arr, int target) {
2    int left = 0;
3    int right = arr.length - 1;
4
5    while (left ___ right) {
6        int mid = left + (right - left) / 2;
7        if (arr[mid] == target) return mid;
8        if (arr[mid] < target) {
9            ___ = mid + 1;
10        } else {
11            ___ = mid - 1;
12        }
13    }
14    return -1;
15}
16

1function binarySearch(arr, target) {
2    let left = 0;
3    let right = arr.length - 1;
4
5    while (left ___ right) {
6        let mid = left + Math.trunc((right - left) / 2);
7        if (arr[mid] == target) return mid;
8        if (arr[mid] < target) {
9            ___ = mid + 1;
10        } else {
11            ___ = mid - 1;
12        }
13    }
14    return -1;
15}
16

<=, left, right

<, left, right

<=, right, left

<, right, left

I don't know

1853. Convert Date Format

Problem

Example

Approach

Example

Solution

SQL

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