2882. Drop Duplicate Rows
Problem Description
The problem presents a DataFrame named customers
with columns customer_id
, name
, and email
. We are informed that there are duplicate records based on the email
column. The task is to remove these duplicate rows, but crucially, we must keep only the first occurrence of each email
. The DataFrame may contain unique customer_id
values and name
values, but some emails
are associated with more than one customer. The goal is to return a DataFrame where all email
addresses appear only once, preserving the record of the first customer who had that email.
Intuition
The drop_duplicates
function from the pandas
library immediately comes to mind for this task. This function is tailor-made for situations like this, where we need to remove duplicate rows based on one or multiple column values. The function comes with the subset
parameter, allowing us to specify on which columns to check for duplicates. In this case, we'll set the subset
to ['email']
, so the function will only consider the email
column for finding duplicates.
By default, drop_duplicates
keeps the first occurrence of a duplicated row, which aligns perfectly with our requirements. We do not need to set the keep
argument as its default value is 'first'
. We can also safely ignore the inplace
parameter, or set it to False
, as we want to return a new DataFrame rather than modify the original customers
DataFrame in place. This provides a simple and efficient solution to the problem that can be implemented and understood with minimal code.
The solution code leverages the described functionality provided by pandas
, and thus with a single line of code, we achieve the desired output, effectively removing all duplicates based on the email
while keeping the first occurrence of each.
Solution Approach
The solution is straightforward due to the robust capabilities of the Pandas library in Python, which is designed to handle and manipulate data in DataFrame structures.
The key steps of the solution are:
-
Import the Pandas library to use its functionalities.
-
Define a function
dropDuplicateEmails
, which takes acustomers
DataFrame as its argument. -
Use the
drop_duplicates
method available in the Pandas library to remove duplicate rows based on specific column values. Thedrop_duplicates
method identifies and removes duplicate rows with the following considerations:- The
subset
parameter specifies the columns to consider for identifying duplicate rows. In our case, this is set to['email']
so that the method looks for duplicates only in theemail
column. - By default, the
keep
parameter is set to'first'
, which means that if duplicates are found, the first occurrence is kept while the subsequent duplicates are removed. This behavior is exactly what we need to solve this problem, so we do not need to specify this parameter explicitly. - The method returns a new DataFrame with the duplicates removed, which we immediately return from our function.
- The
Therefore, the core algorithm involves no complex loops or conditionals due to the high-level abstraction provided by Pandas. The data structure used is the DataFrame itself, and the pattern applied is the direct use of a library function designed for this exact purpose.
The implementation is as follows:
import pandas as pd
def dropDuplicateEmails(customers: pd.DataFrame) -> pd.DataFrame:
return customers.drop_duplicates(subset=['email'])
This elegant and concise implementation leverages Pandas' capabilities to solve the problem with minimal code and time complexity.
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Start EvaluatorExample Walkthrough
Let's walk through a small example to illustrate how the solution approach effectively removes duplicate email addresses and retains only the first occurrence of each.
Suppose we have a small customers
DataFrame that looks like this:
customer_id | name | |
---|---|---|
1 | Alice | alice@example.com |
2 | Bob | bob@example.com |
3 | Alice | alice@example.com |
4 | Charlie | charlie@example.com |
5 | David | bob@example.com |
Here, we can see that Alice
appears twice with the same email (alice@example.com
), and so does Bob
with his email (bob@example.com
). We would like to have only the first occurrence of each unique email address.
Following the solution, this is what we would do:
- Import the pandas library so that we can work with DataFrames.
- Create the
dropDuplicateEmails
function. - Use the
drop_duplicates
method on thecustomers
DataFrame withsubset=['email']
.
When we apply the function dropDuplicateEmails
to our DataFrame, the drop_duplicates
method processes the DataFrame as follows:
- It checks the
email
column for duplicate values since we've setsubset=['email']
. - When it finds the duplicate values
alice@example.com
andbob@example.com
, it keeps the first occurrence of each (the rows withcustomer_id
1 and 2) and discards the other occurrences (the rows withcustomer_id
3 and 5).
The DataFrame returned by the dropDuplicateEmails
function will be:
customer_id | name | |
---|---|---|
1 | Alice | alice@example.com |
2 | Bob | bob@example.com |
4 | Charlie | charlie@example.com |
So the final DataFrame correctly contains only one record for each email address, and the first customers with those emails have been kept. The duplicate rows have been removed, achieving our desired result. The elegance of this solution lies in its simplicity and the use of Pandas' high-level functionality, which makes the code clean, readable, and efficient.
Solution Implementation
1import pandas as pd # Importing the pandas library
2
3def dropDuplicateEmails(customers: pd.DataFrame) -> pd.DataFrame:
4 """
5 Remove duplicate rows from the customers DataFrame based on the 'email' column.
6
7 Parameters:
8 customers (pd.DataFrame): DataFrame containing customer data with an 'email' column.
9
10 Returns:
11 pd.DataFrame: A new DataFrame without duplicate emails.
12 """
13 # Use the drop_duplicates method on the 'customers' dataframe,
14 # specifying 'email' as the subset to identify duplicates by the 'email' column only.
15 unique_customers = customers.drop_duplicates(subset=['email'])
16
17 # Return the resulting DataFrame with duplicates removed.
18 return unique_customers
19
1import java.util.HashMap;
2import java.util.Map;
3import java.util.List;
4import java.util.ArrayList;
5import java.util.Objects;
6
7class Customer {
8 String email;
9 // Other customer fields can be added here
10
11 // Constructor
12 public Customer(String email) {
13 this.email = email;
14 }
15
16 // Email getter
17 public String getEmail() {
18 return email;
19 }
20
21 // Equals and hashCode methods are overridden to use 'email' field for comparison
22 // and to ensure consistent behavior when used as a key in a HashMap.
23 @Override
24 public boolean equals(Object o) {
25 if (this == o) return true;
26 if (!(o instanceof Customer)) return false;
27 Customer customer = (Customer) o;
28 return Objects.equals(email, customer.email);
29 }
30
31 @Override
32 public int hashCode() {
33 return Objects.hash(email);
34 }
35
36 // A toString method for easy printing of customer information.
37 @Override
38 public String toString() {
39 return "Customer{" +
40 "email='" + email + '\'' +
41 '}';
42 }
43}
44
45public class DuplicateEmailsRemover {
46
47 /**
48 * Remove duplicate rows from the list of customers based on the 'email' field.
49 *
50 * @param customers (List<Customer>): A list containing customer objects.
51 * @return List<Customer>: A new list without duplicate emails.
52 */
53 public static List<Customer> dropDuplicateEmails(List<Customer> customers) {
54 // Use a HashMap to track unique emails.
55 Map<String, Customer> uniqueCustomersMap = new HashMap<>();
56
57 // Iterate over the list of customer objects
58 for (Customer customer : customers) {
59 // If the email has not been seen before, add the customer to the map.
60 if(!uniqueCustomersMap.containsKey(customer.getEmail())) {
61 uniqueCustomersMap.put(customer.getEmail(), customer);
62 }
63 }
64
65 // Return the unique customers as a new list (values of the map).
66 return new ArrayList<>(uniqueCustomersMap.values());
67 }
68
69 // A main method to test the functionality
70 public static void main(String[] args) {
71 // Create a list of customers with some duplicate emails
72 List<Customer> customers = new ArrayList<>();
73 customers.add(new Customer("alice@example.com"));
74 customers.add(new Customer("bob@example.com"));
75 customers.add(new Customer("charlie@example.com"));
76 customers.add(new Customer("alice@example.com")); // Duplicate
77
78 // Remove duplicates
79 List<Customer> uniqueCustomers = dropDuplicateEmails(customers);
80
81 // Print out the unique customer list
82 uniqueCustomers.forEach(System.out::println);
83 }
84}
85
1#include <iostream>
2#include <vector>
3#include <string>
4#include <algorithm> // For std::unique and std::stable_sort
5#include "DataFrame.h" // Assuming DataFrame is a fictional class that needs to be included
6
7// Define a custom comparison operator
8bool compareByEmail(const Customer& first, const Customer& second) {
9 return first.getEmail() < second.getEmail();
10}
11
12// Define a custom equality operator
13bool equalByEmail(const Customer& first, const Customer& second) {
14 return first.getEmail() == second.getEmail();
15}
16
17// Remove duplicate rows from the customers DataFrame based on the 'email' column.
18DataFrame dropDuplicateEmails(DataFrame& customers) {
19 // Assuming 'customers' is a DataFrame containing 'Customer' objects
20 // and 'Customer' has a method 'getEmail()' to access the 'email' attribute.
21
22 // First, sort the customers by email using the custom comparison operator
23 std::stable_sort(customers.begin(), customers.end(), compareByEmail);
24
25 // Then, use the unique algorithm with a custom equality operator
26 // unique algorithm will require the duplicates to be next to each other
27 // hence the need for the sort operation beforehand.
28 auto lastUnique = std::unique(customers.begin(), customers.end(), equalByEmail);
29
30 // Erase the non-unique elements from the container
31 customers.erase(lastUnique, customers.end());
32
33 // Return the resulting DataFrame with duplicates removed.
34 return customers;
35}
36
1interface Customer {
2 [key: string]: any; // An index signature to allow any string as a key and its value can be anything
3 email: string; // Ensure that 'email' is always a string
4}
5
6/**
7 * Remove duplicate rows from the customers array based on the 'email' property.
8 *
9 * @param customers - Array containing customer objects with an 'email' property.
10 * @returns A new array without duplicate emails.
11 */
12function dropDuplicateEmails(customers: Customer[]): Customer[] {
13 const seenEmails = new Set<string>(); // To track already encountered emails
14
15 // Use filter to exclude duplicates
16 const uniqueCustomers = customers.filter(customer => {
17 // If seenEmails does not have this email, add it and keep the customer
18 if (!seenEmails.has(customer.email)) {
19 seenEmails.add(customer.email);
20 return true;
21 }
22
23 // Otherwise, it's a duplicate; exclude it by returning false
24 return false;
25 });
26
27 // Return the filtered array without duplicate emails
28 return uniqueCustomers;
29}
30
Time and Space Complexity
The time complexity of the dropDuplicateEmails
function primarily depends on the drop_duplicates
method of the pandas DataFrame, which in turn depends on the size of the input DataFrame.
Time Complexity
For pandas drop_duplicates
method, the time complexity is generally O(n)
, where n
is the number of rows in the DataFrame because it needs to process each row to check for duplicates.
So, the time complexity for the dropDuplicateEmails
function is also O(n)
.
Space Complexity
The space complexity for drop_duplicates
includes the space required to hold the DataFrame and the temporary data structures used to identify duplicates. Typically, it is also O(n)
since a new DataFrame is constructed to store the result without duplicates.
Thus, the space complexity of dropDuplicateEmails
would also be O(n)
.
How does quick sort divide the problem into subproblems?
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